Cyclone lids - performance! (long)
Rob Lee
>Hi Barry (et al) -
Our lid (on the same container) will work better than other lids on the market - the angled inlet combined with a 90 degree outlet in the center gives great performance. From a Physics standpoint - it makes the most sense.
HOWEVER - how well any lid will work for you will depend on you DC, and your collection chamber. If the chamber is too small (or too short) the chips/dust won't settle out. If your system is overpowered - the chips/dust won't settle out. Keep in mind that as the chamber fills - it gets effectively smaller - reducing it's efficiency.
2000 CFM would probably be too much for a 55 gal drum, and a cyclone lid.
I've added a "conceptual" illustration below, that I've posted before in other forums to aid in understanding how seperators work. This is not a scholarly treatise - but you may find it helpful.
Cheers -
Rob
The basic principle behind cyclone lids is the reduction in velocity of an air-stream to the point at which the air movement will no longer carry the chips, or dust. The cyclone itself can be thought of as a very large diameter pipe - in the middle of the dust collection run. The velocity of air entering, and leaving, the cyclone is the same (high) while the velocity of the air within the chamber is low - allowing chips and dust to settle out (the fluid friction acting on the chip/dust is not enough to move it).
The efficiency with which a cyclone will work is dependent on the differential of the air velocities - in essence, directly related to volume (actually cross sectional area) of the separation chamber. This is why performance will diminish as the chamber fills�.
A practical example�. (hopefully sound in that it doesn't violate too many physical laws..)
Let's say a system has an air velocity of 650 cfm, and uses 6" diameter pipe.
650 cfm = 650x12x12x12 = 1123200 cu in/min = 18720 cu in/sec
Air velocity will be 18720/(3**2x3.14) = 662 in/sec in the pipe� (about 37.6 MPH)
Suppose the separation chamber is a garbage can - 20" in diameter, 40" tall -
Mass Flow Rate equation says that (Since mass is conserved) :
m = rVA
Where "r" is fluid density, "V" is velocity, and "A" is cross sectional area�
If we assume that the air density is constant, and mass is conserved - then the change in air velocity will be directly proportional to the change in cross-sectional area
r(1)V(1)A(1) = r(2)V(2) A(2) and r(1) = r(2)
Then V(2) = V(1) x A(1) / A(2)
So the air velocity in the middle of the chamber will be:
V(2) = 662 x ((3**2x3.14)/(40*20)) = 23.4 in/sec (about 1.3 MPH)
And - if the can was half-full, the velocity would be double (the cross-sectional area is halved)..
Realistically, there are many more factors at work here - friction, chamber shape, inlet/outlet orientation, and there will be fluid pressure differences in the air�.
The orientation and positioning of the inlet and outlet are also critical to performance - if "pointed" at each other, conservation of momentum can carry the dust/chips through the "low velocity" section of the chamber into a higher velocity area, where they will continue to be suspended, and pass through the outlet..
The Veritas dust lid has inlet/outlet portions of the dust lid oriented in opposite directions (to reduce the effect of momentum carrying the chips) and - most important - has the outlet located in the plane where the lowest air velocity is - at the center of the drum) � - think of a hurricane -velocity is lowest at the "eye"�
So what does all this mean???
The relationship between CFM and the pipe/chamber size ratio will determine how well a given system will work for you� A separation chamber can be rendered virtually useless if it's overpowered by the dust collector (not enough change in air-stream velocity). That�s why most people who use less powerful DC's (or Shop Vacuum's) report the best performance with trash can type separators�
Hope this helps!!