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Friday Puzzler -- Triangle area

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Friday Puzzler -- Triangle area

#1

Friday Puzzler -- Triangle area

Alex Y

In the following drawing, all the shapes that look like squares are. Accidentally left off the drawing--the sides of the large square are length 5. What is the area of the blue triangle? No trig or "heavy" geometry or algebra required.


Re: Friday Puzzler -- Triangle area

#2

Kent B

Re: Friday Puzzler -- Triangle area

Kent B

Is the plane BU or BD????

Re: Friday Puzzler -- Triangle area

#3

LOL! BU


Re: Friday Puzzler -- Triangle area

#4

Since a square is a two dimensional box,

Larry Barrett

I guess we can say that Kent is thinking outside of the square.

Re: Friday Puzzler -- Triangle area

#5

Re: Friday Puzzler -- Triangle area

Larry Barrett

I think one way to calculate the area involves a lot of square roots. My answer is (with rounding errors) is 2.38.

Re: Friday Puzzler -- Triangle area

#6

Sorry, but no

Alex Y

No square roots required, and answer off by more than rounding.

Re: Friday Puzzler -- Triangle area

#7

Re: Sorry, but no

Larry Barrett

Well, still using same approach (which involves lots of square roots but is pretty straightforward) but with more accuracy, my revised answer is 1.93.

Re: Friday Puzzler -- Triangle area

#8

Re: Sorry, but no

Alex Y

Closer, but correct methods (there are actually a couple of variants) yield an exact answer, with no square roots needed.

Re: Friday Puzzler -- Triangle area

#9

Re: Sorry, but no

Larry Barrett

Third try. I believe the area is 2. No square roots involved.

Re: Friday Puzzler -- Triangle area

#10

Correct!


Re: Friday Puzzler -- Triangle area

#11

And I am sure you saw

Alex Y

that the size of the large square is irrelevant. I just threw in the 5x5 size to divert from resizing that square, which makes solutions easier to see.

Re: Friday Puzzler -- Triangle area

#12

Re: And I am sure you saw

Larry Barrett

You are giving me too much credit (in addition to several hints). I did not see that large square could have sides = x and still have same area for the triangle until just now. This is an interesting problem.

I am surprised that my square root approach did not yield a result closer to the correct answer. The approach is correct, I think, although I needed to know that the larger square is 5x5. I used the fact that if you know three sides of a triangle you can calculate the area using Heron's formula. I found the length of each side using Pythagoras, which resulted in all the square roots.

👍 This page answered my questions

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