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Friday Puzzler -- painted cubes

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Friday Puzzler -- painted cubes

#1

Friday Puzzler -- painted cubes

Alex Y

You are given an unlimited supply of wooden cubes and six cans of paint, with different colors. You are to paint cubes with one color on each face, using all six colors on each.

How many distinctly-colored cubes can you create. Two cubes are distinctly colored if there is no way to rotate them so that each pair of corresponding faces is the same color.

Re: Friday Puzzler -- painted cubes

#2

Re: Friday Puzzler -- painted cubes

Sam Force

With 6 cans of paint the number of "colors" are as endless as the cubes. You did not say that they could not be mixed

Re: Friday Puzzler -- painted cubes

#3

No mixing

Alex Y

But you are correct. I did not make that restriction clear.

What is your answer if each cube must be painted with one face each of red, yellow, blue, orange, green, and purple?

Re: Friday Puzzler -- painted cubes

#4

Re: No mixing

Sam Force

I do not think the number is high, but not positive. 21 comes to mind but I'm not a mathematician

Re: Friday Puzzler -- painted cubes

#5

Sorry, but not 21


Re: Friday Puzzler -- painted cubes

#6

Re: Friday Puzzler -- painted cubes

JohnV

5!/2

Re: Friday Puzzler -- painted cubes

#7

Sorry, but not 60


Re: Friday Puzzler -- painted cubes

#8

Re: Friday Puzzler -- painted cubes

Larry Barrett

Rotations clearly limit the possible variations and trying to picture these rotations is difficult.

Choose one face and call this the top; call the opposite face the bottom.

Put any color on the top and put any of the remaining 5 on the opposite face (5 variations).

Next put any of the remaining 4 colors on one of the adjacent faces and put any of the remaining 3 colors on the opposite face (3 variations).

The remaining 2 colors can now go on either of the remaining 2 faces (2 variations).

So 5x3x2 = 30 possible variations.

Re: Friday Puzzler -- painted cubes

#9

Correct!

Alex Y

And I find that envisioning of physically counting the possibilities much easier than trying to work with combinations or permutations.

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