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Friday Puzzler -- Too Squares

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Friday Puzzler -- Too Squares

#1

Friday Puzzler -- Too Squares

Alex Y

A is a 4x4 square.

B is a 5x5 square.

A and B overlap, with a corner of B at the center of A, and one side of the overlap being of length 3.

What is the area of the overlap?

Re: Friday Puzzler -- Too Squares

#2

Re: Friday Puzzler -- Two Squares

Ed in Leaside

two bits I'd think

Re: Friday Puzzler -- Too Squares

#3

Re: Friday Puzzler -- Too Squares

Henry Higginbotham

Something Gerald Ford should have said . . . .

Re: Friday Puzzler -- Too Squares

#4

"Too"?!?! Squares

Alex Y

Really? Machines are getting pretty good at taking dictation, but can still make you look stupid if you don't proofread!

Re: Friday Puzzler -- Too Squares

#5

Correct!

Alex Y

Good job, Ed, and thanks for correcting my title

Re: Friday Puzzler -- Too Squares

#6

Maybe, Henry

Alex Y

But you totally lost me on your reply.

Re: Friday Puzzler -- Too Squares

#7

Re: Maybe, Henry

Henry Higginbotham

Aside from being an accidental president, Ford is often remembered for accidentally hitting a spectator with a golf ball. My answer was four (Fore!).

But unless I misinterpreted Ed's answer, which you said was correct, maybe I misunderstood the puzzle. I divided the overlap into two triangles, each with an area of 1, and a rectangle with an area of 2.

Re: Friday Puzzler -- Too Squares

#8

Also correct

Alex Y

Sorry I missed your obfuscation of the answer. I almost missed Ed's as well, but two bits equals a quarter, and the overlap is 1/4 of the 4x4 square,

The easy way to see this one is to rotate the 5x5 around the center of the 4x4 by 90, 180, and 270. Each of these three squares will cover a portion of the 4x4 that exactly matches the original, and together they cover the whole 4x4.

Re: Friday Puzzler -- Too Squares

#9

Re: Also correct

Larry Barrett

I started with the 5x5 at 0 degrees (overlapping the 4x4 just in the lower left quadrant). Area of overlap = i/4 of the 4x4. Then rotate 45 degrees so the 5x5 sides hit the corners of the 4x4. Area of overlap by observation is again 1/4 of the 4x4. Since these are equal I assumed the overlap is independent of rotation.

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