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Friday Puzzler -- Bicycle

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Friday Puzzler -- Bicycle

#1

Friday Puzzler -- Bicycle

Alex Y

This is an experiment you could try, but the challenge is to do it as a thought experiment and predict the outcome.

Take a child's bicycle with training wheels (or alternatively, use an adult road bike with someone holding the handlebars only for balance). Pedal it to a point where one pedal is at the top of its travel, and the other is at the bottom. Tie a rope to the bottom pedal. Now kneel about ten feet behind the bike, so that you can pull horizontally on the rope.

What will the bike do when you pull on the rope?

Re: Friday Puzzler -- Bicycle

#2

Re: Friday Puzzler -- Bicycle

john Veerkamp

If you pull it more than the radius it will do two things.

Re: Friday Puzzler -- Bicycle

#3

Re: Friday Puzzler -- Bicycle

Don Orr

My gut response is that the bike would try to move forward but the rope pulling backward would inhibit that.

Re: Friday Puzzler -- Bicycle

#4

Re: Friday Puzzler -- Bicycle

Alex Y

Not sure what happens at one radius. Do you mean the radius of the rear wheel? What will happen before vs after one radius?

Re: Friday Puzzler -- Bicycle

#5

Re: Friday Puzzler -- Bicycle

Alex Y

So are you saying that it would stand still?

Re: Friday Puzzler -- Bicycle

#6

Re: Friday Puzzler -- Bicycle

john Veerkamp

The radius of the pedal's imaginary circle. It will go forward until then and then be pulled/skidded backwards.

Re: Friday Puzzler -- Bicycle

#7

Re: Friday Puzzler -- Bicycle

Larry Barrett

If the coefficient of friction of the rear wheel is low enough, the rear wheel will spin, but the rope will prevent the bicycle from moving forward.

If the coefficient of friction is higher, it may be impossible to turn the pedal, or the rear wheel may jump up and down, with no forward movement.

Re: Friday Puzzler -- Bicycle

#8

Re: Friday Puzzler -- Bicycle

Alex Y

Assume high coefficient of friction.

Re: Friday Puzzler -- Bicycle

#9



Alex Y

Sounds believable, but no.

Re: Friday Puzzler -- Bicycle

#10

Re: Friday Puzzler -- Bicycle

Alex Y

Any engineers or physics 101 students out there want to take a crack at this?

Re: Friday Puzzler -- Bicycle

#11

Hint

Alex Y

What are the forces trying to move the bicycle?

Which is the stronger force?

Re: Friday Puzzler -- Bicycle

#12

Re: Hint

Ed in Leaside

That would depend on gear selection, no?

Re: Friday Puzzler -- Bicycle

#13

Yes, but

Alex Y

I specified a kid's bike or a road bike, and any gear on one of those would give the same answer.

Sounds like you are on the right track.

Re: Friday Puzzler -- Bicycle

#14

Bicycle answer *LINK*

Alex Y

Ed may have gotten this one-his comment about gearing was on target.

The surprising answer is that the bicycle will move backwards. And not only that, it will move backwards (at least initially) FASTER THAN YOU ARE PULLING THE ROPE!

The reason this seems so counter-intuitive, is that we naturally think of the forces applied to the pedal from the perspective of the bike rider, with the rider applying that force. Two things are different in this puzzle: The force is applied from the outside, and while the pedal moves backward with respect to the bike at the bottom, it is still moving forward w.r.t. the road surface.

Below is a video showing the resulting motion, which looks just plain weird-as if he is pushing the pedal with the string.

The physics is actually pretty straight-forward.

Some assumptions about the bike (designed to make calculations easy, but not too far off a real case):

Crank length: 8"

Wheel diameter: 24"

Front sprocket: 40 teeth

Rear sprocket: 20 teeth

There will be two forces acting on the bike, the string trying to pull it backwards and the rear tire trying to push it forward.

Now assume you apply a 12-lb force pulling backward on the bike at the bottom pedal.

That will apply a 96 in-lb torque to the crank axle.

The chain going over the two sprockets will double the rotational speed while cutting the torque in half, to 48 in-lbs.

Applying that torque to the axle of the wheel gives us 4 lb of force applied to the road 12" from the axle center, trying to move the bike forward.

The net then, is a 8 lb force moving the bike backwards.

Now consider the work done, which is preserved (ignoring friction losses); Pulling the string 4" with 12 lbs of force is 48 inch-pounds of work. But we know that only 8 pounds of force was working on the bike, so it had to have moved 6" to "use up" that 48 inch pounds of energy.

And I don't know about you, but that is the kind of physics 101 argument that always had me shaking my head and saying "something must be wrong with that--my intuition tells me it can't be right".

But it is! Watch this. At the end, he does show how a mountain bike with a super-low climbing gear would move forward when you pull the string.


You tube video on bike puzzle

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