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Puzzler -- Envelope please

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Puzzler -- Envelope please

#1

Puzzler -- Envelope please

Alex Y

This "puzzle" is how to explain the apparent paradox of this situation.

You are shown a table with two index cards labeled "Step 1" and "Step 2" and two unlabeled envelopes.

You turn over card number 1 and read that you may pick whichever envelope you want and keep its contents, then read card 2.

You pick an envelope by coin toss and open the envelope, which contains $100.

Now you read card 2, which says that one of the envelopes originally contained exactly twice as much money as the other, and you may switch the money from the envelope you chose for the other envelope, if you so desire.

You reason as follows: There is a 50/50 chance that I picked the larger envelope to begin with . It costs me $100 to swap, and there is a 50% chance I will end up with $200 and a 50% chance I will end up with $50.

.5*$200+.5*$50= $125, so I should make the switch.

Your gut probably tells you this is wrong, and your gut is right -- in fact, with this logic, you don't even need to open the first envelope, just swap it once you have picked it. But then that is the same as picking the second one, so swap it back, and get rich swapping envelopes ad infinitum!

But what is wrong with the expected return reasoning that calls for a switch?

Re: Puzzler -- Envelope please

#2

Re: Puzzler -- Envelope please

Larry Barrett

Suppose card 2 says there is exactly 100 times as much in one envelope as in the other. Now your reward for switching might be $10000, or $1, at a cost of $100.

The error in thinking must be in assigning equal probabilities (1/2) to each outcome. Still not clear to me, but it seems like the probability must be lower for the higher reward. It is a good puzzle.

Re: Puzzler -- Envelope please

#3

Re: Puzzler -- Envelope please

Larry Barrett

If I were a casino owner, setting up tables for this game, for each table that I set up with 100/200 envelopes, I would need to set up 2 tables with 100/50 envelopes in order for the game to be 'fair' - break even over the long run. Thus, for a player, the odds of sitting down at a 100/200 table would be 1/3, and the odds of sitting down at a 100/50 table would be 2/3. So the player's expected return would be (1/3)x(200-100) + (2/3)x(50-100) = 100/3 -(2x50)/3 = 0

Re: Puzzler -- Envelope please

#4

Correct

Alex Y

Sorry for the late response -- I've been offline for a while.

This 100-to-1 version is an excellent way to see the solution. If the envelope that is opened contains $27, it is much more likely to be a random selection of "27" as a count of dollars than a random selection of "2700" as a count of pennies..

But it is VERY hard, IMHO, to see past the idea that the envelope was picked at random between two, so should be 50-50.

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