Friday puzzler -- make-up for last week
Alex Y
Sorry for going AWOL last week. Lee was all over that last one, so let's try a little harder one.
You need to find three 5-digit perfect squares such that:
1) only five digits are used among them (but with repeats and missing digits permitted in any one number)
2) each of the five digits is the count of the number of times another digit appear in the three numbers. None of the digits refers to its own count. I.e., if there are 3s and 7s in the answer, it is possible that "7" appears three times, but "3" does not appear three times.
3) if I told you which digit appeared only once, you would be able to deduce the answer.
But I won't tell you which digit appears only one time, and you can still deduce the answer!
