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Tueday - late entry

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Tueday - late entry

#1

Tueday - late entry

Bill Earl

5 fraternity brothers go into a math test with a plan. Each has studied one of the 5 topics to be covered and plans to telegraph his answer to the others by blinking his eyes in Morse code. The desks in the test room are arranged in a regular grid. It is a full class, so all seats will be occupied.

Can you find a seating arrangement that allows each of the 5 to clearly see each of the others? Can you prove it?

Re: Tueday - late entry

#2

Re: Tueday - late entry *LINK*

-. --- --..-- .- -. -.. -. --- .-.-.- -... ..- - .. .----. .-.. .-.. .... .- ...- . - --- - .... .. -. -.- -- --- .-. . .- -... --- ..- - .-- .... -.--


Morse translator

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#3

Tuesday Hint

Bill Earl

Alex knows the answer but he cant prove it. :\

Considering the grid intersections as integer coordinates, how many ways can you seat someone on the grid?

Re: Tueday - late entry

#4

A start

Larry Barrett

If A is at grid location 0,0, then anyone at immediately adjacent grid locations (i.e at 0,1 1,1 1,0) will be visible.

Also, anyone at a grid location that can be connected by a straight line to A that does not intersect an intermediate grid location. For example, someone at grid location 2,1 would be visible to A, but someone at grid location 2,2 would not because a straight line to 0,0 would intersect 1,1 which is occupied (doesn't matter if one of the five, or not).

So we could have A, B, C, D located at 0,0 0,1 1,1 1,0, all visible to each other. E would then have to be at a location not on the same rows or columns, and satisfying the restriction above with respect to each of the other four. For example, if E was at 3,2 he would be visible to A (at 0,0) B (at 0,1) C (at 1,1), but not to D (at 1,0) because with respect to D, grid location 2,1 is on the same line.

A,B,C,D could be more scattered and still be visible to each other; for example, at 0,0 1,3 2,1 3,4.

So far I can not find an acceptable location for E for either example or prove there is none for these cases (or the more general case).

Re: Tueday - late entry

#5

Correct line of reasoning...


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#6

Re: A start

Alex Y

That's about where I am. I also would note that if A and B are at positions (ra, ca) and (rb, cb), then A and B can see each other iff rb-ra and cb-ca are relatively prime. But I can't get any further. ["yet", he says hopefully!]

Good puzzle, Bill!

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#7

More hints

Bill Earl

Can you make any generalizations about the coordinates of the first 4 seats?

Re: Tueday - late entry

#8

Answer?

Alex Y

Following up on my relatively prime idea, and consistent with Bill's second hint:

There are only four values that the points can have mod 2: (E,E), (E,O), (O,E), and (O,O). Since there are five points, at least two have the same values mod 2. There will be someone sitting exactly half-way between these two, blocking their view of each other.

Re: Tueday - late entry

#9

-... .. -. --. ---   

Bill Earl

Considering the seats as integer coordinates in a two-dimensional grid, the five brothers sit at positions (x1,y1) - (x5,y5).

As Alex correctly observed, each brother's x,y coordinates will be in of four categories:

(Even,Even)

(Even,Odd)

(Odd,Even)

(Odd,Odd)

Therefore two of the five brothers' coordinates must be in the same category. Let's call those two brothers A and B.

Consider the midpoint (xm,ym) between the positions of A and B: ([xA+xB]/2,[yA+yB]/2)

Note that: (xA+xB) and (yA+yB) must both be Even. (because Even + Even = Even and Odd+ Odd = Even). This means that the midpoint of the line must also have integer coordinates meaning that (xm,ym) is a grid position between (xA,yA) and (xB,yB) with someone sitting there.

Therefore brothers A nd B cannot see each other.

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