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Tuesday Puzzle

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Tuesday Puzzle

#1

Tuesday Puzzle

Here is a fairly easy one, but be very aware of the exact wording of the puzzle ;-)

Mr. and Mrs. Jorkins have fifteen children, all born at intervals of one year and a half.

Miss Ada Jorkins, the eldest, had an objection to state her age to the census man, but she

admitted that she was just seven times older than little Johnnie, the youngest of all. What

was Ada's age?

Re: Tuesday Puzzle

#2

28-?

Re: Tuesday Puzzle

#3

What Ken said, less Johny's age

But I didn't catch any tricky wording in the puzzle, so I'm probably off here. Will have to look again after a cup of coffee!

Re: Tuesday Puzzle

#4

Re: Tuesday Puzzle

If I read this right, the census man must have showed up sometime close to the birthday of the second oldest sibling.

Re: Tuesday Puzzle

#5

not quite ;-)

Re: Tuesday Puzzle

#6

no ;-)

Re: Tuesday Puzzle

#7

24.5

Re: Tuesday Puzzle

#8

Dan said "not quite"

But I agree. Waiting to find out the subtlety in wording that we are missing...

Re: Tuesday Puzzle

#9

How About 21?

Re: Tuesday Puzzle

#10

Aha!?!?

Just saw what I may have been missing. If I am right, it is most likely that at least four of their children are adopted or are from a previous marriage.

Re: Tuesday Puzzle

#11

No ;-)

There is a subtle trap in the wording of the problem.

Re: Tuesday Puzzle

#12

Answer has to do with the census man??

Re: Tuesday Puzzle

#13

Re: Aha!?!?

What about twins?

Re: Tuesday Puzzle

#14

Re: Aha!?!?

Never heard of twins born that far apart!!

Re: Tuesday Puzzle

#15

Re: Aha!?!? -- my answer

14

Mr. and Mrs. Jorkins have fifteen children, all born at intervals of one year and a half.

This wording bothered me from the beginning, but I couldn't figure out a way of interpreting it that made a difference. However, if I interpret it as:

Mr. and Mrs. Jorkins have fifteen children, all born at intervals of one year [between some pairs] and a half [year between other pairs -- whence my speculation about adoption or blended family]

then I can assume an integer difference between the oldest's and youngest's ages of 7-13 years. If Johnnie is two and his oldest sister 14, this would work. And it only requires two adoptions (not four as I stated originally). The mother has 13 children born at one-year spacing, and adopts two whose birthdays are in two slots six months off from her birth children's birthdays.

Re: Tuesday Puzzle

#16

not the error

Re: Tuesday Puzzle

#17

Answer

The daughter is 24 and the youngest is 3. The wording in question is "seven times older than little Johnnie". Most interpret this as "seven times as old as", but it actually means "8 times as old as". If Johnnie is 3, then 7 times older than is 21 years older than or 24 years old.

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