Find the ten digit number with the properties that the first digit describes the number of zeros in the number, the second digit is the number of ones, the third digit is the number of twos, ..., and the tenth digit is the number of nines in the number.
In fairness, maybe I shouldn't have labeled it as easier. My daughter gave it to me with her solution, so I didn't get a chance to see how hard it might be.
Start with 9000000001. This is not possible because there are only 8 0's and you did not account for the 1. Next try 8000000010. This also does not work because you do not account for the 1. Tried 2 for the number of 1's because there need to be at least one 1 for the digit representing the number of 0's and another for the 1 counting the one. This forces a 1 in the 2's place to account for the 2. at that point, I have the ones accounted for and the 2 accounted for, all that is left is to count the number of zeros, put that as the first digit and place a 1 in the proper place to account for the first digit. This ends up being 6210001000. 6 zeros, two 1's and one 2. clear as mud? I just did it by trial and error.
I believe there are an indeterminate number of correct answers for this one. One is 5,210,000,091. You can swap the 9 with any of the zero's. You can also substitute any of the numbers 3 through 8 for one or two of the zeros as long as you adjust the first digit to reflect the change.