Re: Monday's answer
I should have titled this the Highland Game, you�ll see why below.
You would be able to easily get 20 but 21 is the maximum I�ve found with minimum waste.
Each side of an octagon that is 12� face to face is 4.9704 on the outside edge and in that board you can get 31 crosscuts
To do it you would have to rip five strips at 1 inch and very carefully cut the pieces out of them with minimum waste.
Then with the remaining 1/2 inch strip you could glue this together to get one strip at 1 inch and you could get 15 more sides out of this one. Total is 170 pieces
This was all done allowing for a 1/8 " kerf.
If you did not glue the final 1/2 inch strip to make a 1 inch side you would only get 18 octagons.
31 pieces per strip and 15 out of the 1/2 inch gives 170 pieces divided by 8
equals 21.25 Again that�s using an 1/8 inch kerf.
There are some formulas to arrive at the length of a side but the easiest to remember is .4142 times the face to face width (12�)
It took some time to find because I haven�t a clue as to how to graphically illustrate how this is done, but the proof of this side length calculation is at http://home.bendbroadband.com/scottish heritage/ocagonnoel.html. That address doesn�t work on my computer (all I get is the home page of bendbroadband), but you can still get there using Google typing: scottish heritage octagon. Two titles will come up Scott Reekie and Noel Reekie. Choose Noel for the proof. Choose Scott for what I originally found. Hooray for Scotland.
Have fun