John K Jordan
>>>Volume= â…“ π (r12 + r1r2 + r22) H
The formula you copied has lost usefulness due to ASCII character issues.
The volume 'V' of a truncated cone (a frustum of a cone) can be calculated, using '^' to represent raising something to a power, '*' for multiplication, '/' for division, and 'pi' for 3.14..., with 'R' and 'r' for the radii of the ends and 'H' for the height,
V = (R^2 + R*r + r^2) * pi * H / 3
or perhaps simpler, avoiding the squaring operations,
V = (R*R + R*r + r*r) * pi * H / 3
That is, unless I made an iPad typo...
If the inside walls are curved instead of straight (quite likely) you can get a very close approximation by stacking several truncated cones (or cylinders) and adding the volume of each. Warning: if you make the segments small and numerous enough you are getting dangerously close to using calculus. Yikes!