Trivia

Subject:
Re: Friday Puzzler -- Circle's radius

Larry Barrett
I don't have an exact solution; in fact so far I don't have any solution.
And I am not sure this sheds any light on the path to an exact solution. But in geometry there is a theorem called the Intersection Chords theorem. This theorem says that if two chords intersect and the two segments of one chord are a and b, and the two segments of the other chord are c and d, then a x b = c x d.
In this problem, the two segments of the horizontal chord are 2 and 6; one segment of the vertical chord is 3 but the other segment is not labeled; call it y. The theorem says that 2 x 6 = 3 x y, so y must be 4.

And the two chords are perpendicular, so that must also be important in finding R.

That's my two cents.

© 1998 - 2017 by Ellis Walentine. All rights reserved.
No parts of this web site may be reproduced in any form or by
any means without the written permission of the publisher.

WOODCENTRAL, P.O. BOX 493, SPRINGTOWN, PA 18081